M0109Double free via call

Reported by the compiler as an error or warning.

mettle explain M0109

An allocation is freed both by a callee that takes ownership and by the caller (or by two consuming calls).

Fix: decide which side owns the pointer and free only there.

Related

• E0001Lexical error
• E0002Syntax error
• E0003Semantic error
• E0004Type mismatch
• E0005Scope error
• E0006I/O error
• E0007Internal compiler error
• M0101Use after free